Integrand size = 21, antiderivative size = 93 \[ \int \frac {\sin (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=-\frac {3 \cos (c+d x)}{2 d \sqrt [3]{a+a \sin (c+d x)}}+\frac {\cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5}{6},\frac {3}{2},\frac {1}{2} (1-\sin (c+d x))\right )}{2^{5/6} d \sqrt [6]{1+\sin (c+d x)} \sqrt [3]{a+a \sin (c+d x)}} \]
-3/2*cos(d*x+c)/d/(a+a*sin(d*x+c))^(1/3)+1/2*cos(d*x+c)*hypergeom([1/2, 5/ 6],[3/2],1/2-1/2*sin(d*x+c))*2^(1/6)/d/(1+sin(d*x+c))^(1/6)/(a+a*sin(d*x+c ))^(1/3)
Time = 0.25 (sec) , antiderivative size = 84, normalized size of antiderivative = 0.90 \[ \int \frac {\sin (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=-\frac {3 \cos (c+d x) \left (2 \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {1}{2},\frac {7}{6},\sin ^2\left (\frac {1}{4} (2 c+\pi +2 d x)\right )\right )+\sqrt {2-2 \sin (c+d x)}\right )}{2 d \sqrt {2-2 \sin (c+d x)} \sqrt [3]{a (1+\sin (c+d x))}} \]
(-3*Cos[c + d*x]*(2*Hypergeometric2F1[1/6, 1/2, 7/6, Sin[(2*c + Pi + 2*d*x )/4]^2] + Sqrt[2 - 2*Sin[c + d*x]]))/(2*d*Sqrt[2 - 2*Sin[c + d*x]]*(a*(1 + Sin[c + d*x]))^(1/3))
Time = 0.36 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {3042, 3230, 3042, 3131, 3042, 3130}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sin (c+d x)}{\sqrt [3]{a \sin (c+d x)+a}} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {\sin (c+d x)}{\sqrt [3]{a \sin (c+d x)+a}}dx\) |
\(\Big \downarrow \) 3230 |
\(\displaystyle -\frac {1}{2} \int \frac {1}{\sqrt [3]{\sin (c+d x) a+a}}dx-\frac {3 \cos (c+d x)}{2 d \sqrt [3]{a \sin (c+d x)+a}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {1}{2} \int \frac {1}{\sqrt [3]{\sin (c+d x) a+a}}dx-\frac {3 \cos (c+d x)}{2 d \sqrt [3]{a \sin (c+d x)+a}}\) |
\(\Big \downarrow \) 3131 |
\(\displaystyle -\frac {\sqrt [3]{\sin (c+d x)+1} \int \frac {1}{\sqrt [3]{\sin (c+d x)+1}}dx}{2 \sqrt [3]{a \sin (c+d x)+a}}-\frac {3 \cos (c+d x)}{2 d \sqrt [3]{a \sin (c+d x)+a}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {\sqrt [3]{\sin (c+d x)+1} \int \frac {1}{\sqrt [3]{\sin (c+d x)+1}}dx}{2 \sqrt [3]{a \sin (c+d x)+a}}-\frac {3 \cos (c+d x)}{2 d \sqrt [3]{a \sin (c+d x)+a}}\) |
\(\Big \downarrow \) 3130 |
\(\displaystyle \frac {\cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5}{6},\frac {3}{2},\frac {1}{2} (1-\sin (c+d x))\right )}{2^{5/6} d \sqrt [6]{\sin (c+d x)+1} \sqrt [3]{a \sin (c+d x)+a}}-\frac {3 \cos (c+d x)}{2 d \sqrt [3]{a \sin (c+d x)+a}}\) |
(-3*Cos[c + d*x])/(2*d*(a + a*Sin[c + d*x])^(1/3)) + (Cos[c + d*x]*Hyperge ometric2F1[1/2, 5/6, 3/2, (1 - Sin[c + d*x])/2])/(2^(5/6)*d*(1 + Sin[c + d *x])^(1/6)*(a + a*Sin[c + d*x])^(1/3))
3.2.6.3.1 Defintions of rubi rules used
Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-2^(n + 1/2))*a^(n - 1/2)*b*(Cos[c + d*x]/(d*Sqrt[a + b*Sin[c + d*x]]))*Hypergeome tric2F1[1/2, 1/2 - n, 3/2, (1/2)*(1 - b*(Sin[c + d*x]/a))], x] /; FreeQ[{a, b, c, d, n}, x] && EqQ[a^2 - b^2, 0] && !IntegerQ[2*n] && GtQ[a, 0]
Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[a^IntPar t[n]*((a + b*Sin[c + d*x])^FracPart[n]/(1 + (b/a)*Sin[c + d*x])^FracPart[n] ) Int[(1 + (b/a)*Sin[c + d*x])^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && EqQ[a^2 - b^2, 0] && !IntegerQ[2*n] && !GtQ[a, 0]
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(-d)*Cos[e + f*x]*((a + b*Sin[e + f*x])^m/( f*(m + 1))), x] + Simp[(a*d*m + b*c*(m + 1))/(b*(m + 1)) Int[(a + b*Sin[e + f*x])^m, x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && !LtQ[m, -2^(-1)]
\[\int \frac {\sin \left (d x +c \right )}{\left (a +a \sin \left (d x +c \right )\right )^{\frac {1}{3}}}d x\]
\[ \int \frac {\sin (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=\int { \frac {\sin \left (d x + c\right )}{{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {1}{3}}} \,d x } \]
\[ \int \frac {\sin (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=\int \frac {\sin {\left (c + d x \right )}}{\sqrt [3]{a \left (\sin {\left (c + d x \right )} + 1\right )}}\, dx \]
\[ \int \frac {\sin (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=\int { \frac {\sin \left (d x + c\right )}{{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {1}{3}}} \,d x } \]
\[ \int \frac {\sin (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=\int { \frac {\sin \left (d x + c\right )}{{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {1}{3}}} \,d x } \]
Timed out. \[ \int \frac {\sin (c+d x)}{\sqrt [3]{a+a \sin (c+d x)}} \, dx=\int \frac {\sin \left (c+d\,x\right )}{{\left (a+a\,\sin \left (c+d\,x\right )\right )}^{1/3}} \,d x \]